10x^2+4=13x

Solution for 10x^2+4=13x equation:

10x^2+4=13x

We move all terms to the left:

10x^2+4-(13x)=0

a = 10; b = -13; c = +4;
Δ = b2-4ac
Δ = -132-4·10·4
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-3}{2*10}=\frac{10}{20}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+3}{2*10}=\frac{16}{20}
=4/5
$